This posting contains a summary of optical facts for photographers. It is more detailed that a FAQ file, but less so than a text book. It covers focusing, apertures, bellows correction, depth of field, hyperfocal distance, diffraction, the Modulation Transfer Function and illumination.

*
This note gives a tutorial on lenses and gives some common lens
formulas. I attempted to make it between an FAQ (just simple facts)
and a textbook. I generally give the starting point of an idea, and
then skip to the results, leaving out all the algebra. If any part of
it is too detailed, just skip ahead to the result and go on.
*

*It is in 6 parts. The first gives formulas relating subject and image
distances and magnification, the second discusses f-stops, the third
discusses depth of field, the fourth part discusses diffraction, the
fifth part discusses the Modulation Transfer Function, and the sixth
illumination. The sixth part is authored by John Bercovitz. Sometime
in the future I will edit it to have all parts use consistent notation
and format.
*

*The theory is simplified to that for lenses with the same medium (eg
air) front and rear: the theory for underwater or oil immersion lenses
is a bit more complicated.
*

"Nodal points" are the two points such that a light ray entering the front of the lens and headed straight toward the front nodal point will emerge going straight away from the rear nodal point at exactly the same angle to the lens's axis as the entering ray had. The nodal points are identical to the principal points when the front and rear media are the same, e.g. air, so for most practical purposes the terms can be used interchangeably.

In simple double convex lenses the two principal points are somewhere inside the lens (actually 1/n-th the way from the surface to the center, where n is the index of refraction), but in a complex lens they can be almost anywhere, including outside the lens, or with the rear principal point in front of the front principal point. In a lens with elements that are fixed relative to each other, the principal points are fixed relative to the glass. In zoom or internal focusing lenses the principal points may move relative to the glass and each other when zooming or focusing.

When a camera lens is focused at infinity, the rear principal point is exactly one focal length in front of the film. To find the front principal point, take the lens off the camera and let light from a distant object pass through it "backwards". Find the point where the image is formed, and measure toward the lens one focal length. With some lenses, particularly ultra wides, you can't do this, since the image is not formed in front of the front element. (This all assumes that you know the focal length. I suppose you can trust the manufacturers numbers enough for educational purposes.)

S_{o}subject (object) to front principal point distance. S_{i}rear principal point to image distance f focal length M magnification 1/S_{o}+ 1/S_{i}= 1/f M = S_{i}/S_{o}(S_{o}-f)*(S_{i}-f) = f^2 M = f/(S_{o}-f) = (S_{i}-f)/f

If we interpret S_{i}-f as the "extension" of the lens beyond infinity
focus, then we see that this extension is inversely proportional to a
similar "extension" of the subject.

For rays close to and nearly parallel to the axis (these are called "paraxial" rays) we can approximately model most lenses with just two planes perpendicular to the optic axis and located at the principal points. "Nearly parallel" means that for the angles involved, theta ~= sin(theta) ~= tan(theta). ("~=" means approximately equal.) These planes are called principal planes.

The light can be thought of as proceeding to the front principal plane, then jumping to a point in the rear principal plane exactly the same displacement from the axis and simultaneously being refracted (bent). The angle of refraction is proportional the distance from the center at which the ray strikes the plane and inversely proportional to the focal length of the lens. (The "front principal plane" is the one associated with the front of the lens. I could be behind the rear principal plane.)

Apertures, f-stop, bellows correction factor, pupil magnification

We define more symbols

D diameter of the entrance pupil, i.e. diameter of the aperture as seen from the front of the lens N f-number (or f-stop) D = f/N, as in f/5.6 N_{e}effective f-number (corrected for "bellows factor", but not absorption)

Light from a subject point spreads out in a cone whose base is the
entrance pupil. (The entrance pupil is the virtual image of the
diaphragm formed by the lens elements in front of the diaphragm.) The
fraction of the total light coming from the point that reaches the
film is proportional to the solid angle subtended by the cone. If the
entrance pupil is distance y in front of the front nodal point, this
is approximately proportional to D^2/(S_{o}-y)^2. (Usually we can ignore
y.) If the magnification is M, the light from a tiny subject patch of
unit area gets spread out over an area M^2 on the film, and so the
brightness on the film is inversely proportional to M^2. With some
algebraic manipulation and assuming y=0 it can be shown that the
relative brightness is

(D/S_{o})^2/M^2 = 1/(N^2 * (1+M)^2).

Thus in the limit as S_{o} -> infinity and thus M -> 0, which is the usual
case, the brightness on the film is inversely proportional to the
square of the f-stop, N, and independent of the focal length.

For larger magnifications, M, the intensity on the film in is somewhat less then what is indicated by just 1/N^2, and the correction is called bellows factor. The short answer is that bellows factor when y=0 is just (1+M)^2. We will first consider the general case when y != 0.

Let us go back to the original formula for the relative brightness on the film.

(D/(S_{o}-y))^2/M^2

The distance, y, that the aperture is in front of the front nodal point, however, is not readily measurable. It is more convenient to use "pupil magnification". Analogous to the entrance pupil is the exit pupil, which is the virtual image of the diaphragm formed by any lens elements behind the diaphragm. The pupil magnification is the ratio of exit pupil diameter to the entrance pupil diameter.

p pupil magnification (exit_pupil_diameter/entrance_pupil_diameter)

For all symmetrical lenses and most normal lenses the aperture appears the same from front and rear, so p~=1. Wide angle lenses frequently have p<1, while true telephoto lenses usually have p>1. It can be shown that y = f*(1-1/p), and substituting this into the above equation and carrying out some algebraic manipulation yields that the relative brightness on the film is proportional to

1/(N^2 ( 1 + M/p)^2)

Let us define N_{e}, the effective f-number, to be an f-number with the
lens focused at infinity (M=0) that would give the same relative
brightness on the film (ignoring light loss due to absorption and
reflection) as the actual f-number N does with magnification M.

N_{e}= N*(1+M/p)

An alternate, but less fundamental, explanation of bellows correction
is just the inverse square law applied to the exit pupil to film
distance. N_{e} is exit_pupil_to_film_distance/exit_pupil_diameter.

It is convenient to think of the correction in terms of f-stops (powers of two). The correction in powers of two (stops) is 2*Log2(1+M/p) = 6.64386 Log10(1+M/p). Note that for most normal lenses y=0 and thus p=1, so the M/p can be replaced by just M in the above equations.

Consider the situation of a "main subject" that is perfectly in focus, and an "alternate subject point" this is in front of or behind the subject.

S_{oa}alternate subject point to front principal point distance S_{ia}rear principal point to alternate image point distance h hyperfocal distance C diameter of circle of confusion c diameter of largest acceptable circle of confusion N f-stop (focal length divided by diameter of entrance pupil) N_{e}effective f-stop N_{e}= N * (1+M/p) D the aperture (entrance pupil) diameter (D=f/N) M magnification (M=f/(S_{o}-f))

The diameter of the circle of confusion can be computed by similar triangles, and then solved in terms of the lens parameters and subject distances. For a while let us assume unity pupil magnification, i.e. p=1.

When S_{o} is finite

C = D*(SWhen S_{ia}-S_{i})/S_{ia}= f^2*(S_{o}/S_{oa}-1)/(N*(S_{o}-f))

C = f^2/(N S_{oa})

Note that in this formula C is positive when the alternate image point is behind the film (i.e. the alternate subject point is in front of the main subject) and negative in the opposite case. In reality, the circle of confusion is always positive and has a diameter equal to Abs(C).

If the circle of confusion is small enough, given the magnification in printing or projection, the optical quality throughout the system, etc., the image will appear to be sharp. Although there is no one diameter that marks the boundary between fuzzy and clear, .03 mm is generally used in 35mm work as the diameter of the acceptable circle of confusion. (I arrived at this by observing the depth of field scales or charts on/with a number of lenses from Nikon, Pentax, Sigma, and Zeiss. All but the Zeiss lens came out around .03mm. The Zeiss lens appeared to be based on .025 mm.) Call this diameter c.

If the lens is focused at infinity (so the rear principal point to film distance equals the focal length), the distance to closest point that will be acceptably rendered is called the hyperfocal distance.

h = f^2/(N*c)

If the main subject is at a finite distance, the closest alternative point that is acceptably rendered is at at distance

S_{close}= h S_{o}/(h + (S_{o}-F))

and the farthest alternative point that is acceptably rendered is at distance

Sexcept that if the denominator is zero or negative, S_{far}= h S_{o}/(h - (S_{o}- F))

We call S_{far}-S_{o} the rear depth of field and S_{o}-S_{close} the front depth
field.

A form that is exact, even when P != 1, is

depth of field = c N_{e}/ (M^2 * (1 +or- (S_{o}-f)/h1)) = c N (1+M/p) / (M^2 * (1 +or- (N c)/(f M))

where h1 = f^2/(N c), ie the hyperfocal distance given c, N, and f and assuming P=1. Use + for front depth of field and - for rear depth of field. If the denominator goes zero or negative, the rear depth of field is infinity.

This is a very nice equation. It shows that for distances short with
respect to the hyperfocal distance, the depth of field is very close
to just c*N_{e}/M^2. As the distance increases, the rear depth of field
gets larger than the front depth of field. The rear depth of field is
twice the front depth of field when S_{o}-f is one third the hyperfocal
distance. And when S_{o}-f = h1, the rear depth of field extends to
infinity.

If we frame a subject the same way with two different lenses, i.e. M is the same both both situations, the shorter focal length lens will have less front depth of field and more rear depth of field at the same effective f-stop. (To a first approximation, the depth of field is the same in both cases.)

Another important consideration when choosing a lens focal length is how a distant background point will be rendered. Points at infinity are rendered as circles of size

C = f M / N

So at constant subject magnification a distant background point will be blurred in direct proportion to the focal length.

This is illustrated by the following example, in which lenses of 50mm and 100 mm focal lengths are both set up to get a magnification of 1/10. Both lenses are set to f/8. The graph shows the circle of confusions for points as a function of the distance behind the subject.

circle of confusion (mm) # # *** 100mm f/8 # ... 50mm f/8 0.8 # ******* # ********* # ********* # **** # ***** # **** 0.6 # **** # ***** ....... # *** .................. # ** ............. 0.4 # **** ......... # *** .... # ** ..... # * .... # **.. 0.2 # **. # .*. # ** #* *###################################################################### 0 # 250 500 750 1000 1250 1500 1750 2000 distance behind subject (mm)

The standard .03mm circle of confusion criterion is clear down in the ascii fuzz. The slope of both graphs is the same near the origin, showing that to a first approximation both lenses have the same depth of field. However, the limiting size of the circle of confusion as the distance behind the subject goes to infinity is twice as large for the 100mm lens as for the 50mm lens.

2 J1(x)/x, where x = 2 phi Pi R/lambda

and where R is the radius of the aperture, lambda is the wavelength of the light, and J1 is the first order Bessel function. The normalization is relative to the field strength at the center. The power (intensity) is proportional to the square of this function.

The field strength function forms a bell-shaped curve, but unlike the classic E^(-x^2) one, it eventually oscillates about zero. Its first zero at 1.21967 lambda/(2 R). There are actually an infinite number of lobes after this, but about 86% of the power is in the circle bounded by the first zero.

Relative field strength *** 1 # **** # ** 0.8 # * # ** # * # ** # * 0.6 # * # * # * 0.4 # * # * # ** 0.2 # ** # ** # ** ***************** ###############################*###################*****################### # ***** ****** # 0.5 1 1.5****** 2 2.5 3 Angle from axis (relative to lambda/diameter_of_aperture)

Approximating the aperture-to-film distance as f and making use of the fact that the aperture has diameter f/N, it follows directly that the diameter of the first zero of the diffraction pattern is 2.43934*N*lambda. Applying this in a normal photographic situation is difficult, since the light contains a whole spectrum of colors. We really need to integrate over the visible spectrum. The eye has maximum sensitive around 555 nm, in the yellow green. If, for simplicity, we take 555 nm as the wavelength, the diameter of the first zero, in mm, comes out to be 0.00135383 N.

As was mentioned above, the normally accepted circle of confusion for depth of field is .03 mm, but .03/0.00135383 = 22.1594, so we can see that at f/22 the diameter of the first zero of the diffraction pattern is as large is the acceptable circle of confusion.

A common way of rating the resolution of a lens is in line pairs per mm. It is hard to say when lines are resolvable, but suppose that we use a criterion that the center of the dark area receive no more than 80% of the light power striking the center of the lightest areas. Then the resolution is 0.823 /(lambda*N) lpmm. If we again assume 555 nm, this comes out to 1482/N lpmm, which is in close agreement with the widely used rule of thumb that the resolution is diffraction limited to 1500/N lpmm. However, note that the MTF, discussed below, provides another view of this subject.

The 2-dimensional Fourier transform of the point spread function is known as the optical transfer function (OTF). The value of this function along any radius is the fourier transform of the line spread function in the same direction. The modulation transfer function is the absolute value of the fourier transform of the line spread function.

Equivalently, the modulation transfer function of a lens is the ratio of relative image contrast divided by relative subject contrast of a subject with sinusoidally varying brightness as a function of spatial frequency (e.g. cycles per mm). Relative contrast is defined as (Imax-Imin)/(Imax+Imin). MTF can also be used for film, but since film has a non-linear characteristic curve, the density is first transformed back to the equivalent intensity by applying the inverse of the characteristic curve.

For a lens, the MTF can vary with almost every conceivable parameter, including f-stop, subject distance, distance of the point from the center, direction of modulation, and spectral distribution of the light. The two standard directions are radial (also known as sagittal) and tangential.

The MTF for an an ideal lens (ignoring unavoidable effect of diffraction) is a constant 1 for spatial frequencies from 0 to infinity at every point and direction. For a practical lens it starts out near 1, and falls off with increasing spatial frequency, with the falloff being worse at the edges than at the center. Adjacency effects in film can make the MTF of film be greater than 1 in certain frequency ranges.

An advantage of the MTF as a measure of performance is that under some circumstances the MTF of the system is the product (frequency by frequency) of the (properly scaled) MTFs of its components. Such multiplication is always allowed when the phase of the waves is lost at each step. Thus it is legitimate to multiply lens and film MTFs or the MTFs of a two lens system with a diffuser in the middle. However, the MTFs of cascaded ordinary lenses can legitimately be multiplied only when a set of quite restrictive and technical conditions is satisfied.

As an example of some OTF/MTF functions, below are the OTFs of pure diffraction for an f/22 aperture, the OTF induced by a .03mm circle of confusion of a de-focused but otherwise perfect and diffraction free lens, and the combination of these. (Note that these cannot be multiplied.)

Let lambda be the wavelength of the light, and spf the spatial frequency in cycles per mm.

For diffraction the formula is

OTF(lambda,N,spf) = 2/Pi (ArcCos(lambda N spf) - lambda N spf Sqrt(1-(lambda N spf)^2)) if lambda N spf <=1 = 0 if lambda N spf >=1

Note that for lambda = 555 nm, the OTF is zero at spatial frequencies of 1801/N cycles per mm and beyond.

For a circle of confusion of diameter C,

OTF(C,spf) = 2 J1(Pi C spf)/(Pi C spf)where, again J1(x) is the first order Bessel function. This goes negative at certain frequencies. Physically, this would mean that if the test pattern were lighter right on the optical center then nearby, the image would be darker right on the optical center than nearby. The MTF is the absolute value of this function. Some authorities use the term "spurious resolution" for spatial frequencies beyond the first zero.

When there is a combination of diffraction and focus error dz (which by itself would cause a circle of confusion of diameter dz/N), the OTF is given by the following. It involves an integration which must be done numerically. Let s = lambda N spf, and a = Pi spf dz / N. Then the OTF is given by

OTF = 4/(Pi a) integral y=0 to sqrt(1-s^2) of sin(a(sqrt(1-y^2)-s)) dy for s < 1 0 for s >= 1

This formula is an approximation that is best at small apertures.

Here is a graph of the OTF of the f/22 diffraction limit, a .03mm circle of confusion, and the combined effect.

OTF * 1 ***** # +$$* # +$* # + *$ $$$$ Diffraction 0.8 # + **$ **** Circle of confusion # ++ *$$ ++++ Combined diffraction and circle of confusion # + * $$ # + * $ 0.6 # ++* $$ # +* $$ # * $$ # * $$ 0.4 # * $$ # *++++ $$ # * +++++ $$$$ # * +++++$$$$ 0.2 # * ++++$$ # * +$$$ # * $$$$***************** #######################**##################**$$$$$$$$$$$$$$$$$******$$$ 0 # ** ***** *** # 20 40 ***** ***** 80 100 120 # ** Spatial Frequency (cycles/mm)

Note how the combination is not the product of each of the effects taken separately.

Some authorities present MTF in a log-log plot.

The classic paper on the MTF for the combination of diffraction and focus error is H.H. Hopkins, "The frequency response of a defocused optical system," Proceedings of the Royal Society A, v. 231, London (1955), pp 91-103. Reprinted in Lionel Baker (ed), Optical Transfer Function: Foundation and Theory, SPIE Optical Engineering Press, 1992, pp 143-153.

Light flux, for the purposes of illumination engineering, is measured in lumens. A lumen of light, no matter what its wavelength (color), appears equally bright to the human eye. The human eye has a stronger response to some wavelengths of light than to other wavelengths. The strongest response for the light-adapted eye (when scene luminance >= .001 Lambert) comes at a wavelength of 555 nm. A light-adapted eye is said to be operating in the photopic region. A dark-adapted eye is operating in the scotopic region (scene luminance </= 10^-8 Lambert). In between is the mesopic region. The peak response of the eye shifts from 555 nm to 510 nm as scene luminance is decreased from the photopic region to the scotopic region. The standard lumen is approximately 1/680 of a watt of radiant energy at 555 nm. Standard values for other wavelengths are based on the photopic response curve and are given with two-place accuracy by the table below. The values are correct no matter what region you're operating in - they're based only on the photopic region. If you're operating in a different region, there are corrections to apply to obtain the eye's relative response, but this doesn't change the standard values given below.

Wavelength, nm Lumens/watt Wavelength, nm Lumens/watt 400 0.27 600 430 450 26 650 73 500 220 700 2.8 550 680

Following are the standard units used in photometry with their definitions and symbols.

- Luminous flux, F,
- is measured in lumens.
- Quantity of light, Q,
- is measured in lumen-hours or lumen-seconds. It is the time integral of luminous flux.
- Luminous Intensity, I,
- is measured in candles, candlepower, or candela (all the same thing). It is a measure of how much flux is flowing through a solid angle. A lumen per steradian is a candle. There are 4 pi steradians to a complete solid angle. A unit area at unit distance from a point source covers a steradian. This follows from the fact that the surface area of a sphere is 4 pi r^2.
- Lamps are measured in MSCP, mean spherical candlepower.
- If you multiply MSCP by 4 pi, you have the lumen output of the lamp. In the case of an ordinary lamp which has a horizontal filament when it is burning base down, roughly 3 steradians are ineffectual: one is wiped out by inter- ference from the base and two more are very low intensity since not much light comes off either end of the filament. So figure the MSCP should be multiplied by 4/3 to get the candles coming off perpendicular to the lamp filament. Incidentally, the number of lumens coming from an incandescent lamp varies approximately as the 3.6 power of the voltage. This can be really important if you are using a lamp of known candlepower to calibrate a photometer.
- Illumination (illuminance), E,
- is the
*areal density*of incident luminous flux: how many lumens per unit area. A lumen per square foot is a foot-candle; a one square foot area on the surface of a sphere of radius one foot and having a one candle point source centered in it would therefore have an illumination of one foot-candle due to the one lumen falling on it. If you substitute meter for foot you have a meter-candle or lux. In this case you still have the flux of one steradian but now it's spread out over one square meter. Multiply an illumination level in lux by .0929 to convert it to foot-candles. (foot/meter)^2= .0929. A centimeter- candle is a phot. Illumination from a point source falls off as the square of the distance. So if you divide the intensity of a point source in candles by the distance from it in feet squared, you have the illumination in foot candles at that distance. - Luminance, B,
- is the
*areal intensity*of an extended diffuse source or an extended diffuse reflector. If a perfectly diffuse, perfectly reflecting surface has one foot-candle (one lumen per square foot) of illumination falling on it, its luminance is one foot-Lambert or 1/pi candles per square foot. The total amount of flux coming off this perfectly diffuse, perfectly reflecting surface is, of course, one lumen per square foot. Looking at it another way, if you have a one square foot diffuse source that has a luminance of one candle per square foot (pi times as much intensity as in the previous example), then the total output of this source is pi lumens. If you travel out a good distance along the normal to the center of this one square foot surface, it will look like a point source with an intensity of one candle.To contrast: Intensity in candles is for a point source while luminance in candles per square foot is for an extended source - luminance is intensity per unit area. If it's a perfectly diffuse but not perfectly reflecting surface, you have to multiply by the reflectance, k, to find the luminance.

Also to contrast: Illumination, E, is for the incident or incoming flux's areal

*density*; luminance, B, is for reflected or outgoing flux's areal*intensity*.Lambert's law says that an perfectly diffuse surface or extended source reflects or emits light according to a cosine law: the amount of flux emitted per unit surface area is proportional to the cosine of the angle between the direction in which the flux is being emitted and the normal to the emitting surface. (Note however, that there is no fundamental physics behind Lambert's "law". While assuming it to be true simplifies the theory, it is really only an empirical observation whose accuracy varies from surface to surface. Lambert's law can be taken as a definition of a perfectly diffuse surface.)

A consequence of Lambert's law is that no matter from what direction you look at a perfectly diffuse surface, the luminance on the basis of

*projected*area is the same. So if you have a light meter looking at a perfectly diffuse surface, it doesn't matter what the angle between the axis of the light meter and the normal to the surface is as long as all the light meter can see is the surface: in any case the reading will be the same.There are a number of luminance units, but they are in categories: two of the categories are those using English units and those using metric units. Another two categories are those which have the constant 1/pi built into them and those that do not. The latter stems from the fact that the formula to calculate luminance (photometric Brightness), B, from illumination (illuminance), E, contains the factor 1/pi. To illustrate:

B = (k*E)(1/pi) B

_{fl}= k*E where: B = luminance, candles/foot^2 B_{fl}= luminance, foot-Lamberts k = reflectivity 0<k<1 E = illuminance in foot-candles (lumens/ foot^2)Obviously, if you divide a luminance expressed in foot-Lamberts by pi you then have the luminance expressed in candles /foot^2. (B

_{fl}/pi=B)Other luminance units are:

stilb = 1 candle/square centimeter sb apostilb = stilb/(pi X 10^4)=10^-4 L asb nit = 1 candle/ square meter nt Lambert = (1/pi) candle/square cm L

Below is a table of photometric units with short definitions.

Symbol Term Unit Unit Definition Q light quantity lumen-hour radiant energy lumen-second as corrected for eye's spectral response F luminous flux lumen radiant energy flux as corrected for eye's spectral response I luminous intensity candle one lumen per steradian candela one lumen per steradian candlepower one lumen per steradian E illumination foot-candle lumen/foot^2 lux lumen/meter^2 phot lumen/centimeter^2 B luminance candle/foot^2 see unit def's. above foot-Lambert = (1/pi) candles/foot^2 Lambert = (1/pi) candles/centimeter^2 stilb = 1 candle/centimeter^2 nit = 1 candle/meter^2

Note: A lumen-second is sometimes known as a Talbot.

To review:

- Quantity of light, Q,
- is akin to a quantity of photons except that here the number of photons is pro-rated according to how bright they appear to the eye.
- Luminous flux, F,
- is akin to the time rate of flow of photons except that the photons are pro-rated according to how bright they appear to the eye.
- Luminous intensity, I,
- is the solid-angular density of luminous flux. Applies primarily to point sources.
- Illumination, E,
- is the areal density of incident luminous flux.
- Luminance, B,
- is the areal intensity of an extended source.

The basis of using a light meter is the fact that a light meter uses the Additive Photographic Exposure System, the system which uses Exposure Values:

Efrom which, for example:_{v}= A_{v}+ T_{v}= S_{v}+ B_{v}where: E_{v}= Exposure Value A_{v}= Aperture Value = lg_{2}N^2 where N = f-number T_{v}= Time Value = lg_{2}(1/t) where t = time in sec.s S_{v}= Speed Value = lg_{2}(0.3 S) where S = ASA speed B_{v}= Brightness Value = lg_{2}B_{fl}lg_{2}is logarithm base 2

Aand therefore:_{v}(N=f/1) = 0 T_{v}(t=1 sec) = 0 S_{v}(S=ASA 3.125) E B_{v}( B_{fl}= 1 foot-Lambert) = 0

B_{fl}= 2^B_{v}E_{v}(S_{v}= 0) = B_{v}

From the preceeding two equations you can see that if you set the
meter dial to an ASA speed of approximately 3.1 (same as S_{v} = 0), when
you read a scene luminance level the E_{v} reading will be B_{v} from which you
can calculate B_{fl}. If you don't have an ASA setting of 3.1 on your dial, just
use ASA 100 and subtract 5 from the E_{v} reading to get B_{v}.
(S_{v}@ASA100=5)

E_{image}= (t pi B)/[4 N^2 (1+m)^2] or: E_{image}= (t B_{fl})/[4 N^2 (1+m)^2] where: E_{image}is in foot-candles (divide by .0929 to get lux) t is the transmittance of the lens (usually .9 to .95 but lower for more surfaces in the lens or lack of anti-reflection coatings) B is the object luminance in candles/square foot B_{fl}is the object luminance in foot-Lamberts N is the f-number of the lens m is the image magnification

- G.E. Miniature Lamp Catalog
- Gilway Technical Lamp Catalog
- Lenses in Photography Rudolph Kingslake Rev.Ed.c1963 A.S.Barnes
- Applied Optics & Optical Engr. Ed. by Kingslake c1965 Academic Press
- The Lighting Primer Bernard Boylan c1987 Iowa State Univ.
- University Physics Sears & Zemansky c1955 Addison-Wesley

Copyright (C) 1993, 1994, 1995 David M. Jacobson

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